Am-241 has a half life of roughly 432 years. How much of a 100 gram sample would remain after 1,296 years?
Answer to the nearest tenth.

12.5 g

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 432 years.

Original amount (N₀) = 100 g

Time (t) = 1296 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t½) = 432 years.

Time (t) = 1296 years

Number of half-lives (n) =?

n = t / t½

n = 1296 / 432

n = 3

Thus, 3 half-lives has elapsed.

Finally, we shall determine the amount of the isotope remaining. This can be obtained as follow:

Original amount (N₀) = 100 g

Number of half-lives (n) = 3

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2³ × 100

N = 1/8 × 100

N = 0.125 × 100

N = 12.5 g

Thus, 12.5 g of the isotope is remaining.

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.