A closed gas system initially has volume and pressure of 6400mL and 1.49atm with the temperature unknown. If the same closed system has values of 657 torrs, 9660mL, and 2450C, what was the initial temperature in K?

The initial temperature was 588 Kelvin

Explanation:

The combined gas equation is,

where,

= initial pressure of gas = 1.49 atm

= final pressure of gas = 657 torr = 0.864 atm   (760 torr = 1atm)

= initial volume of gas = 6400 ml

= final volume of gas = 9660 ml

= initial temperature of gas = ?

= final temperature of gas =

Now put all the given values in the above equation, we get:

The initial temperature was 588 Kelvin

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.