According to the reaction below, how many grams of KCl (potassium chloride) can be formed from 70.90 g of chlorine with excess potassium? 2K + Cl2 ---> 2 KCl

149.1 g KCl

Explanation:

2 K  +  Cl₂  ⇒  2 KCl

This is your chemical equation.  Use this equation to figure out the stoichiometry between Cl₂ and KCl.  According to the equation, for every 2 moles of KCl, you need 1 mole of Cl₂, making the ratio between KCl and Cl₂ 2/1.

First, convert grams of Cl₂ to moles of Cl₂.  The molar mass is 70.906 g/mol.

(70.90 g Cl₂)/(70.906 g/mol) = 0.9999 mol Cl₂

Convert moles of Cl₂ to moles of KCl using the stoichiometric relationship.

(0.9999 mol Cl₂) × (2 mol KCl/1 mol Cl₂) = 1.9998 mol KCl

Convert moles of KCl to grams of KCl.  The molar mass is 74.55 g/mol.

(1.998 mol KCl) × (74.55 g/mol KCl) = 149.1 g KCl

You will produce 149.1 g KCl.

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