How many moles of AgNO3 are needed to produce 6.75 moles of copper (II) nitrate Cu(NO3)2 upon reacting with excess copper (Cu)? 2AgNO3 + Cu --> 2Ag + Cu(NO3)2

Students conversion factor: 6.75 mol Cu(NO3)2 x 1 mol Cu(NO3)2/2 mol AgNO3
Question 1 options:

The student chose the wrong conversion factor.

The student chose the correct conversion factor, but need to flip it to make units cancel.

The student chose the correct conversion factor, but needs to add a second to finish the problem.

There is nothing wrong the problem is ready to be solved.