Find the enthalpy of the following reaction at 25 °C using average bond enthalpies. CH3CH3 (g) + 7/2 O2 (g) → 2 CO2 (g) + 3 H2O (g)

Average bond enthalpies (kJ/mol): E(C–C)=347, E(C–H)=413, E(O= O)=498,

E(C= O)=804, E(O–H)=463

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

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