Consider the equations below. A
CH (9) C(s)+2H (9) AH, = 74.6 kJ
C(s) +2012(9) ► CCI (9) AH, = -95.7 kJ
2H2(9)+2012(9) — 4HCl(9) AH2 =-184.6 kJ
CH (9)+ 4C12() → CC (9)+ 4HCI(g) AH, = -205.7 kJ
B
Complete the following based on the diagram.
D
Arrow A:
С
Arrow B:
Arrow C:
Arrow D:

Arrow A:  

✔ 74.6 kJ

Arrow B:  

✔ exothermic

Arrow C:  

✔ has a magnitude that is less than that of B

Arrow D:  

✔ represents the overall enthalpy of reaction

Explanation:

74.6 kJ

exothermic

has a magnitude that is less than that of B

represents the overall enthalpy of reaction

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.