1.Pretend that the exponent that [Sn2+ ] is raised to in the rate law expression is 0.9527. Pretend that the exponent that [H3O+ ] is raised to in the rate law expression is 0.9552. Finally, pretend that for one of your runs that the kexpt = 0.0040, [H3O+ ] = 0.7656, and [Sn2+ ] = 0.0069. Determine the rate constant, k, for that run. 2.The other five rate constants you determined from the other five runs are:

0.9748, 0.9956, 1.0115, 0.9792, 0.9780

2.What is the average rate constant from the six kinetic runs (5 are listed here and the 6th is found from the previous problem)?

3.What is the percent relative average deviation (%RAD) from the average of the rate constant?

the temperature of the gas, in k, not celsius.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2