How many Grams of Nitrogen are in 2.086 x 10 9 G of nh4no3

730×10 6 g

Explanation:

each one mole of NH4NO3 has 2 moles of nitrogen (2×14)

N NH4NO3

2×14 14+(4×1) +14+(3×16)

28 80

? 2.086 × 10 9

2.086× 10 9 ×28 ÷80 = 730 × 10 6 g of Nitrogen

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.