Given a Ksp for AgBr of 5.0 * 10–13, what happens when 50 ml of 0.002 M AgNO3 and 50 mL of 0.002 M NaBr are mixed?

A precipitate will be produced

Explanation:

The Ksp of AgBr is:

AgBr(s) → Ag⁺ + Br⁻

5.0x10⁻¹³ = [Ag⁺] Br⁻]

Where [] are the concentrations in equilibrium of each ion.

And if Q is:

Q = [Ag⁺] Br⁻]

Where the concentrations are actual concentrations of each ion

We can say:

IF Q >= Ksp, a precipitate will be produced

IF Q < Ksp, no precipitate will be produced.

the molar concentrations are:

[AgNO₃] = [Ag⁺] = 0.002M * (50mL / 100mL) = 0.001M

Because 50mL is the volume of the AgNO₃ solution and 100mL the volume of the mixture of both solutions.

[NaBr] = [Br⁻] = 0.002M * (50mL / 100mL) = 0.001M

Q = [0.001M] * [0.001M]

Q = 1x10⁻⁶

As Q > Ksp,

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