If the energy of a photon of light is 3.37 x 10–19 J, what is the frequency of the light? A. 1.12 x 10–27 s –1 B. 8.90 x 1026 s –1 C. 5.09 x 1014 s –1 D. 6.70 x 10–44 s –1 E. 1.01 x 10–10 s –1

The appropriate alternative is option C "".

Explanation:

The given value is:

Energy of photon,

E =

As we know,

h =

Now,

The frequency of the light will be:

⇒  

On substituting the given values, we get

⇒  

On solving, we get

⇒                    

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

1 a

2 d

3 a

4 c

explanation: