Imagine that you are in chemistry lab and need to make 1.00 L of a solution with a pH of 2.60. You have in front of you

100 mL of 6.00×10−2 M HCl,
100 mL of 5.00×10−2 M NaOH, and
plenty of distilled water.

You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOH. Once you realize your error, you assess the situation. You have 80.0 mL of HCl and 87.0 mL of NaOH left in their original containers.

Assuming the final solution will be diluted to 1.00 L , how much more HCl should you add to achieve the desired pH?
Express your answer to three significant figures and include the appropriate units.

15.1 mL of the HCl solution should be added

Explanation:

First off, let's use the definition of pH to find the desired number of H⁺ moles:

pH = -log[H⁺]

2.80 = -log[H⁺]

= [H⁺]

[H⁺] = 1.58 x 10⁻³ M

Then we use the definition of Molarity [C=n/V]:

[H⁺] = 1.58 x 10⁻³ M = molesH⁺ / 1.00 L

molesH⁺ =  1.58 x 10⁻³

So in the end there needs to be 1.58 x10⁻³ moles of H⁺ to achieve the desired pH.

Now let's calculate the added amounts of HCl and NaOH

mL HCl = 100 - 84 = 16 mL = 0.016 L

mL NaOH = 100 - 88 = 12 mL = 0.012 L

mol HCl = 0.016 L * 7.00x10⁻² M = 1.12x10⁻³ mol HCl = mol H⁺

mol HCl = 0.012 L * 5.00x10⁻² M = 6.0x10⁻⁴ mol NaOH = mol OH⁻

OH⁻ reacts with H⁺, producing water. So the moles of H⁺ remaining in the solution are:

1.12x10⁻³ - 6.0x10⁻⁴ = 5.2x10⁻⁴ mol H⁺

This means that the moles of H⁺ that we need to add are:

1.58x10⁻³ - 5.2x10⁻⁴ = 1.06x10⁻³ mol H⁺

Finally we calculate the required volume of HCl:

C = n/V

7.00 x10⁻² M = 1.06x10⁻³ mol H⁺ / V

V = 0.0151 L = 15.1 mL

trigonal pyramidal

tetrahedral

trigonal planar

bent

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.