what would be the value of 'G' on the surface of earth if it's mass was twice & its radius half of what it is how?​

What would be the value of g on the surface of the earth if its mass was twice and its radius half of what it is now ? g2=8g1 Thus , the value of g on the surface of the earth would be eight times the present value.

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Explanation:

What could be the value of g on the surface of Earth if its mass were twice as large, and the radius also twice what it is now?

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Andreas Xi

Updated 1 year ago

G would be half of what it is now, since it is proportional to mass and inversely proportional to distance squared. Such a planet would be only a little more dense than water, quite similar to Neptune, but smaller.

See below for the answer to the (completely different) original question:

What would be the value of g on the surface of the earth if its mass was twice as large and its radius half of what it is now?

G would be eight times larger, since it is proportional to mass and inversely proportional to distance squared. [Thanks to Niels for pointing out an earlier mistake]

The Earth would need to be 16 times as dense, though, which is quite impossible. The density of rock is around 3 g/cm^3, of iron around 8 and the Earth overall (consisting mostly of those two materials, including compression) around 6. The densest known material is around 22 g/cm^3 (Osmium), which is only roughly 4 times as much. Even when you consider increased compression, no planet could possibly satisfy your conditions, even if it were made of pure Osmium.

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