Explain HOW this chemical reaction is NOT balanced correctly. SiF4 + 2 H2O --> H4SiO4 + 2 H2SiF6

there is more atoms of each element on the right.

Explanation:

On the left of the arrow you have:

Si-1

F-4

H-4

O-2

On the right of the arrow you have:

Si-3

F-6

H-8

O-4

A balanced equation always has the same amount of each element on the left of the arrow (the reactants) as the right (the products). This isn’t balanced because you have a lot more of each element on the right.

Explanation:

On the reactant side,

*the atomicity of silicon in silicon flouride(SiF4) is 1

*the atomicity of flourine in SiF4 is 4

*the atomicity of hydrogen in two molecules of water is 4

*the atomicity of oxygen in two molecules of water is 2

On the product side,

*the atomicity of hydrogen in orthosilicic acid(H4SiO4) + atomicity of hydrogen in hexaflourosilic acid =8

*the atomicity of silicon in H4SiO4 + atomicity of silicon in 2H2SiF6 =3

*the atomicity of oxygen in H4SIO4 is 4

*the atomicity of flourine in 2H2SIF6 is 12

RS. PS

Si= 1. 3

H= 4. 8

O= 2. 4

F= 4. 12

The correct EQ is ;

3SiF4 + 4H2O >H4SIO4 + 2H2SiF6

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"