5. 1.250 g of an alloy which is 90.00 % Ag and 10.00 % Cu is reacted with nitric acid producing AgNO3 and Cu(NO3)2 dissolved in solution. To the solution of the nitrate compounds is added a piece of copper wire that reacts only with the AgNO3 in solution to precipitate all of the silver, and produce additional Cu(NO3)2 (aq) . (The equation for this single-replacement reaction is: AgNO3(aq) + Cu(s)  Cu(NO3)2(aq) + 2 Ag(s) ) The resulting solution containing all of the Cu(NO3)2 produced by the above processes is treated with excess zinc to precipitate the entire amount of copper (ll) ion present. ( The equation for this step is Cu(NO3)2(aq) + Zn(s)  Zn(NO3)2(aq) + Cu(s) ) What mass of copper will be precipitated?