Determine how many moles of water (H2O) are formed from the combustion of 7.50 x 1023 molecules of propane (C3H8). 1 C3H8 (g) + 5 O2 (g) ⟶ 3 CO2 (g) + 4 H2O (g)

4.98 moles of H₂O

Explanation:

The balanced chemical equation for the combustion of propane is:

C₃H₈ (g) + 5 O₂ (g) ⟶ 3 CO₂ (g) + 4 H₂O (g)

That means that 1 mol of propane (C₃H₈) produces 4 moles of water (H₂O).

We know that 1 mol is equal to 6.022 x 10²³ molecules. So, we convert the molecules of propane to moles as follows:

7.50 x 10²³ molecules C₃H₈ x 1 mol/6.022 x 10²³ molecules = 1.245 mol C₃H₈

Now, we use the stoichiometric ratio 4 mol H₂O/1 mol C₃H₈ derived from the chemical equation to calculate the moles of water produced:

1.245 mol C₃H₈ x 4 mol H₂O/1 mol C₃H₈ = 4.98 mol H₂O

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