Describe how to prepare 100.00 mL of a 0.250 M sodium chloride (NaCl) solution using sodium chloride powder.

The answer to your question is given below.

Explanation:

We'll begin by converting 100 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100 mL × 1 L / 1000 mL

100 mL = 0.1 L

Next, we shall determine the number of mole of NaCl in the solution. This can be obtained as follow:

Volume of solution = 0.1 L

Molarity of NaCl = 0.250 M

Mole of NaCl =?

Molarity = mole / Volume

0.250 = mole of NaCl / 0.1

Cross multiply

Mole of NaCl = 0.250 × 0.1

Mole of NaCl = 0.025 mole

Finally, we shall determine the mass of 0.025 mole of NaCl. This can be obtained as follow:

Mole of NaCl = 0.025 mole

Molar mass of NaCl = 23 + 35.5

= 58.5 g/mol

Mass of NaCl =?

Mole = mass / Molar mass

0.025 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.025 × 58.5

Mass of NaCl = 1.46 g

Thus, to prepare the solution, weigh out 1.46 g of NaCl and dissolve in 1 L of water.

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