A sample of nitrogen occupies a volume of 3.0 L at 0 ℃ and 1.21 atm pressure. To which temperature (in ℃) should the gas be cooled in order to halve its volume while maintaining a constant pressure?

Thegas should be cooled to -136.5°C.

Explanation:

Volume of a gas is directly proportional to its temperature on the kelvin scale. This is called Charles' law.

Initially, the gas had a volume of 3.0 L at 0°C(273 K).

We have to have the temperature at which the volume of the gas will be 1.5 L.

Let V1=3 L, T1=273 K, V2=1.5 L, T2=?

By Charles' law,

V1/T1=V2/T2

T2

=(V2×T1)/V1

=(1.5 L×273K)/3L

=136.5 K

=(136.5-273)°C

= -136.5 °C

the answer for sodium is 0.186

the answer for rubidium is 0.251

just did the assignment and the answer was #1 +2 n