Calculate the volume (in mL) of 0.100 M Na, C03 needed to produce 1.00 g of CaCO3(s). There is an excess of CaCl2.

Molar mass of calcium carbonate = 100.09 g/mol

Volume of sodium carbonate = ?mL

The correct answer is a

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

They are like other investigations? say there was a murder u have to do blood test and finger prints which run through a lab.