How many grams of MgBr2 are needed to create 3.0L of a 4.5M aqueous solution of magnesium bromide?

2486 g

Explanation:

First we calculate how many moles of MgBr₂ are required to create such a solution, using the definition of molarity and the given volume and concentration:

Now we convert 13.5 moles of MgBr₂ into grams, using its molar mass:

indium, and thallium have three electrons i think

the product of the pressure and volume is also constant