(b) 30% (0)<br />10%<br />Find the H. C.F of 5a² and 20a²b <br />(<br />Find the L. C.M. of 3a²b and 2ab²<br /><br />Write28-3 + a + 4 as a single fraction<br />22<br />(a) 3a + 7 (b) a +7 (c) 3a -1 (d) 3a +<br />2 2<br />2 2<br />Find the value of x. if 4x + 7 = 5x + 6 (a) (b)<br />(0)-2<br />4+7​

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

cutt.ly/4zZs6GM

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2