A solution contains 6 mg isopropanol dissolved in 2 kg H2O. The isopropanol concentration is a.3% isopropanol.
b.3 M isopropanol.
c.3 m isopropanol.
d.3 ppm isopropanol.

Option D. 3 ppm isopropanol

Explanation:

The following data were obtained from the question:

Mass of isopropanol = 6 mg

Mass of water = 2 Kg

Isopropanol concentration =?

The isopropanol concentration can be obtained as follow:

Concentration = mass isopropanol / mass of water

Isopropanol concentration = 6 mg / 2 kg

Isopropanol concentration = 3 mg/Kg

Finally, we shall convert 3 mg/Kg to ppm. This can be obtained as follow:

1 mg/Kg = 1 ppm

Therefore,

3 mg/Kg = 3 ppm

Thus, we can conclude that the concentration of isopropanol is 3 ppm.

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