Perform the calculations for: a) the volume of oxygen required for the combustion of 120g of magnesium in the presence of oxygen air;
b)the volume of air where the volume of oxygen is located
c) the number of moles of magnesium oxide obtanied.

2. what volume will occupy under standard contitions:
a)22g hydrogen H2
b)5 mol P2O3

3. what volume will occupy under normal conditions:
a) 0.05 mol CH4
b)3.01×10 23 molecule Cl2

please please help me with the questions in the photo and with the ones that i have written up this text pleasee

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explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

did anyone actually do this? like if anyone has submitted this i rly need .