Two vessels contain separately 30 cm' nitrogen at 100mmHg pressure and 20 cm' of oxygen at 200 mmHg and they are
connected by taps to a third vessel containing 50 cm of hydrogen
at 250 mmHg. If the taps are opened and the gases are allowed to
mix until equilibrium is attained: determine
(a)
The partial pressure of each of three gases
(b)
The total pressure of the gaseous mixture.
wacheated with an eycases​

it is b that is the answer.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole