Given the following equation, how many grams of pbco3 will dissolve when exactly 1.0 l of 1.00 m h+ is added to 6.00 g of pbco3?
when the equation is pbco3(s) + 2h(+)(aq) = pb(2+)(aq) + h2o(l) + co2(g)
explain in detail, step by step

6 grams of lead carbonate wlll get easily dissolve in 1 L of 1.0 M solution.

Explanation:

Moles of (n):

n = 1 mole

According to reaction 2 moles of dissolves 1 mole of then , 1 mole will dissolve ; moles of that is 0.5 moles

Mass of the compund:

=Number of moles of compound × Molar mass of compound

Mass of dissolved :

=

1 L of 1.0 M solution can dissolve 133.605 grams of lead carbonate. So, 6 grams of lead carbonate wlll get easily dissolve in 1 L of 1.0 M solution.