114. The following equation describes the oxidation of ethanol to acetic acid by potassium permanganate! 3C, H,OH + 4KMnO4 → 3HC, H,O2 + 4MnO+4KOH + H2O
5.00 g of ethanol (46.07 g/mol) and an excess of aqueous KMnO4 are reacted, and 5.99 g of HC2H302 (60.05
g/mol) result. What is the percent yield?

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Explanation:

The following equation describes the oxidation of ethanol to aceticacid by potassium permanganate:

3C2H5OH +4KMnO4-->3HC2H3O2 +4MnO2 + 4KOH + H2O

5.0 g of ethanol and an excess of aqueous KMnO4 arereacted, and 5.9 g HC2H3O2 result.What is the percent yield?

a. 100%

b. 91%

c. 67%

d. 30%

e. 5.9 g HC2H3O2 is impossible since it represcents more than a100% yield.

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation: