How many grams are there in 9.03 x 1023 molecules of CO2?

The correct answer is - 66g.

Explanation:

Given:

molecules of CO2 = 9.03 x 10^23

We know:

1 mole of any substance = 6.02x10^23 molecules. (Avogadro's number)

M (CO2) = 12 + (2x16) = 12 + 32 = 44g

Solution:

The mass of CO2 with 9.03x10^23 molecules would be:

44g of CO2 = 6.02x10^23 molecules.

So, the mass in grams of CO2 (X) = 9.03x10^23 molecules

Xg of CO2 = (44x9.03x10^23)/6.02x10^23 = 66g

Thus, the correct answer would be - 66gm.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm