C. A 35.5 g cube of aluminum initially at 48.5° C is submerged into 105.3 g of water at 15.4
What is the final temperature of both substances at thermal equilibrium?

The final temperature of both substances at thermal equilibrium is 17.3°C

Explanation:

To calculate the final temperature of both substances at thermal equilibrium -:

First , we calculate the heat of A1  cube as follows -

            q= mSΔT

(where q = heat of the cube , m = mass of cube , S= specific heat of cube  {0.902j/g°C}, T = Temperature )

Putting the values given in the question ,

        °°

Now , calculate the heat of water -

         q=mSΔT

Putting values from the question ,

           °°

              =

          Now ,

Heat lost by water A1= Heat gained by water [negative sign about heat lost]

      °°

       °=

        °

        = 17.3°C

Therefore , the final temperature of both substances at thermal equilibrium is 17.3°C