135 g of aluminum initially at 400.°C is added to an unknown mass of water (initially at 25°C). When thermal equilibrium is reached, the system has a temperature of 80.°C. Find the mass of water. Note c = .89 J/g°C for Al

981.82g or 0.982 kg

Explanation:

I believe this is Physics, but okay!

We have to use the Specific Heat Capacity formula here.

Heat energy = mass x specific heat capacity x change in temperature

mass = Heat energy/(specific heat capacity x change in temperature)

Heat energy is measured in Joules so we need to find out how to do this.

To find an amount in Joules, we are given 135g and 0.89J/g°C.

135g x 400°C = 54000 to give us g°C

54000 x 0.89 = 48060  By multiplying these two values, we get given 48060J.

This is because: g°C/1 x J/g°C = Joules on it's own

mass = (48060)/[0.89 x (80 - 25)]

mass = 981.82g

the answer is b. dilution

confused

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