Se dispone de 100 mL de una disolución 0.15M de hidróxido de potasio (KOH).Calcula el pH de la solución. Recuerda que el
hidróxido de potasio es una base fuerte que sufre disociación total
en disolución acuosa.

Cucl2 + 2nano3 cu(no3)2 + 2nacl what is the percent yield of nacl if 31.0 g of cucl2 reacts with excess nano3 to produce 21.2 g of nacl? 49.7% 58.4% 63.6% 78.7%

In the millikan oil drop experiment they determined that every drop had a charge which was a while number multiple of -1.60x10^-19. if a drop has a total charge of -9.60x10^-19 then how many excess electrons are contained within the drop?

Can you me with this i really appreciate it