Chemistry, 19.03.2021 21:10 kcarstensen59070

2KClO₃ → 2KCl + 3O₂ If 25.0 g of KClO₃ decompose, what mass of O₂ will form? *

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Answer from: Buddy01

approximately 15.1 grams.

Explanation: The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want. Change 25 grams of potassium chlorate to moles. Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron. 1 K x 39 grams/mole+1 Cl x 35.4grams/ mole+3 O x 16 grams/ mole = 122.4 grams / mole Potassium Chlorate 25 122.4 = moles. 2.05 moles of Potassium Chlorate. There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride. 2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride. Find the gram molecular mass of Potassium Chloride. 1 K x 39 = 39+1 Cl x 35.4 = 35.4 = 74.4 grams / mole. 2.05 moles x 74.4 grams/ mole = 15.2 grams

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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