Given the equation: 3Mg(S) + 2(NH4)3BO3(aq) → Mg3(BO3)2(aq) + 6NH4(aq) How many moles of Mg(s) will you need to completely react with 1.0mol of (NH4)3BO3(aq)? 1.5mol Mg
1.25mol Mg
1.75mol Mg
2.0mol Mg

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a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.