Calculate the change in heat (Q) that occurs when 38.68grams of steam at 304°C cools to liquid water at 197°C. (cp = 4.184 J/g°C)

Change in heat (Q) = -1.7316 x 10⁴

Explanation:

Given:

Mass m = 38.68 g

Change in temperature Δt = (197-304) = -107°C

Specific heat C = 4.184 J/g°C

Find:

Change in heat (Q)

Computation:

Change in heat (Q) = (C)(m)(Δt)

Change in heat (Q) = (4.184)(38.68)(-107)

Change in heat (Q) = -1.7316 x 10⁴

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