If 1.08 g of sodium sulfate reacts with an excess of phosphoric acid, how much sulfuric acid is produced?

 0.745 g of will be produced from  1.08 g of sodium sulfate

Explanation:

To calculate the moles :

is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry :

3 moles of produce = 3 moles of

Thus 0.0076 moles of will require=  of

Mass of

Thus 0.745 g of will be produced from  1.08 g of sodium sulfate

the answer is barium and copper bromide