Calculate the number of atoms of iron produced from 100.0 g of Iron (iii) oxide. Will give brainliest, thank you for the help!

The strategy here would be to convert mass to moles and then from moles to the number of atoms.

100.0 g of iron(iii) oxide, or Fe2O3, has a molar mass of 159.687 g/mol. To convert the mass into the number of moles, divide the mass by the molar mass: (100.0 g)(159.687) = 0.6262 moles Fe2O3.

1 mole of any substance is, by definition, equal to 6.022 • 10^23 units of that substance. So to compute the number atoms contained in 0.6262 moles of Fe2O3, multiply (0.6262)(6.022 • 10^23) = 3.771 • 10^23 atoms of iron(iii) oxide, which is your answer (given to four significant figures).

If it releases 5 tons a day and there are 7 days a take that answer and multiply by 5 percent (0.05) to find the amount released in one week. leave a comment if you need more .