The equilibrium constant for the dissociation of hydrofluoric acid is 6.6 x 10-4. If 2M HF is allowed to reach equilibrium, what will be the concentration of the fluoride atom? HF(aq) <-> H+(aq) + F-(aq)

Sorry i dont understand the question can you rephase it?

Yeah, but what are you trying to ask?

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj

The lewis structure for co2 has a total of  16  valence electrons.  hoped i can i get brainliest