SO2(g) reacts with Cl2(g) to produce SO2Cl2(g), according to the equation above. A mixture of 1.00atm of SO2(g) and 1.00atm of Cl2(g) is placed in a rigid, evacuated 1.00L container, and the reaction mixture is allowed to reach equilibrium at a certain temperature. The table below shows the initial partial pressure of each gas and the equilibrium partial pressures of SO2(g) and SO2Cl2(g) at the same temperature. Which of the following indicates the equilibrium value of PCl2 and the approximate value of the equilibrium constant Kp ?

the answer is learned

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole