Que cantidad de agua sera necesaria agregar a 25 gramos de sulfato de cobre II para preparar una solución al 15% m/m?

141.7 de Agua deben ser adicionados para preparar la solución deseada

Explanation:

El %m/m se define como la masa de soluto (En este caso, sulfato de cobre) en 100g de solución (Sulfato de cobre + Agua):

%m/m = Masa soluto / Masa soluto + Masa Agua *100

Reemplazando con los datos del problema:

15%m/m: 25g CuSO₄ / (25g CuSO₄ + Xg H₂O) * 100

0.15 = 25 /(25+X)

3.75 + 0.15X = 25

0.15X = 21.25

X = 141.7 de Agua deben ser adicionados para preparar la solución deseada

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2