How many moles of PCl5 can be produced from 54.0 g of Cl2 (and excess P4)?

0.304 mole of PCl₅.

Explanation:

We'll begin by calculating the number of mole in 54 g of Cl₂. This can be obtained as follow:

Mass of Cl₂ = 54 g

Molar mass of Cl₂ = 2 × 35.5 = 71 g/mol

Mole of Cl₂ =?

Mole = mass /molar mass

Mole of Cl₂ = 54 / 71

Mole of Cl₂ = 0.76 mole

Finally, we shall determine the number of mole of PCl₅ produced by the reaction of 54 g (i.e 0.76 mole) of Cl₂.

The equation for the reaction is given below:

10Cl₂ + P₄ —> 4PCl₅

From the balanced equation above,

10 moles of Cl₂ reacted to produce 4 moles of PCl₅.

Therefore, 0.76 mole of Cl₂ of will react to produce = (0.76 × 4)/10 = 0.304 mole of PCl₅.

Thus, 0.304 mole of PCl₅ were obtained from the reaction.