Please use the below reaction to answer this question. N2 + 3H2 -> 2NH3

How many liters of nitrogen gas will I need to produce 65.4 liters of NH3 at STP?

32.7 L

Explanation:

Step 1: Write the balanced equation

N₂ + 3 H₂ ⇒ 2 NH₃

Step 2: Calculate the moles corresponding to 65.4 L of NH₃ at STP

At STP, 1 mole of NH₃ occupies 22.4 L.

65.4 L × 1 mol/22.4 L = 2.92 mol

Step 3: Calculate the number of moles of N₂ required to form 2.92 moles of NH₃

The molar ratio of N₂ to NH₃ is 1:2. The moles of N₂ required are 1/2 × 2.92 mol = 1.46 mol

Step 4: Calculate the volume occupied by 1.46 moles of N₂ at STP

At STP, 1 mole of N₂ occupies 22.4 L.

1.46 mol × 22.4 L/1 mol = 32.7 L