A gas takes up 50.0 L while at STP. How much volume will the same gas occupy if the pressure remains constant and the temperature increases to 380 K?

69.6L

Explanation:

Using Charles law equation:

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question, a gas takes up 50.0 L while at STP. A gas at STP will possess an initial temperature of 273K. Hence;

V1 = 50.0 L

V2 = ?

T1 = 273K

T2 = 380K

Using V1/T1 = V2/T2

50/273 = V2/380

CROSS MULTIPLY

380 × 50 = 273 × V2

19000 = 273V2

V2 = 19000 ÷ 273

V2 = 69.59

V2 = 69.6L

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