How many moles of KCl will be produced from the decomposition of 5.0 grams of KClO3.

Answer

Decomposition of KClO  

3

​  

 takes place as:

2KClO  

3

​  

(s)→2KCl(s)+3O  

2

​  

(g)

2 mole of KClO  

3

​  

=3 mole of O  

2

​  

∵ 3 mole O  

2

​  

 formed by 2 mole KClO  

3

​  

∴2.4 mole of O  

2

​  

 will be formed by:

(  

3

2

​  

×2.4) mol KClO  

3

​  

= 1.6 mole of KClO  

3

​  

.  

Mass of KClO  

3

​  

 = Number of moles ×  Molar mass  

=1.6×122.5=196g

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o