How would you prepare a 1 L solution of 3 M MgO? A.
Put 3 grams of MgO in the beaker and add enough water to reach the 1 L mark.

B.
Put 3 grams of MgO in the beaker and add exactly 1 L of water.

C.
Put 120 grams of MgO in the beaker and add enough water to reach the 1 L mark.

D.
Put 120 grams of MgO in the beaker and add exactly 1 L of water.

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

it takes on an electronical energy

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b