What would the molarity of a solution be if you took 10 mL of a 13 m stock solution and made it 300 mL solution

0.43 M

Explanation:

Use the dilution equation: M1V1 = M2V2

M1 = 13 M

V1 = 10 mL

M2 = ?

V2 = 300 mL

Solve for M2 --> M2 = M1V1/V2

M2 = (13 M)(10 mL) / (300 mL) = 0.43 M

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