Ammonium chloride is produced in the thermochemical equation NH3 (g) + HCl (g) → NH4Cl (s) ΔH = –176 kJ. How many moles of NH4Cl have been produced if the change in enthalpy is –528 kJ?

3 moles of NH₄Cl

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Finally, we shall determine the number of mole of NH₄Cl produced when the change in enthalphy (ΔH) is –528 kJ. This can be obtained as follow:

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Therefore, Xmol of NH₄Cl will be obtained when the change in enthalphy (ΔH) is –528 kJ i.e

Xmol of NH₄Cl = –528 / –176

Xmol of NH₄Cl = 3 moles

Thus, 3 moles of NH₄Cl where obtained from the reaction.

i think its 100.

hope this !