Suppose a 14-gram sample of iron is heated from 20.0°c to 25.0°c. the specific heat of iron is 0.11 cal/g°c. how much heat energy was absorbed by the iron? 38.5 cal 7.7 cal 636 cal 69.3 cal

Answer : The heat energy absorbed by the iron is 7.7 cal.

Explanation :

Formula used :

where,

Q = heat absorb = ?

m = mass of iron = 14 g

c = specific heat of iron =

= change in temperature

= initial temperature =

= final temperature =

Now put all the given value in the above formula, we get:

Therefore, the heat energy absorbed by the iron is 7.7 cal.

gas

explanation:

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when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.