If the football indoors had a volume of 5.33 L at 21degrees celsuis, what is the volume of the football outside where the temp is 10C (temp must be in K) MUST SHOW WORK

5.13 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 5.33 L

Initial temperature (T₁) = 21 °C

Final temperature (T₂) = 10 °C

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 21 °C

Initial temperature (T₁) = 21 °C + 273

Initial temperature (T₁) = 294 K

Final temperature (T₂) = 10 °C

Final temperature (T₂) = 10 °C + 273

Final temperature (T₂) = 283 K

Finally, we shall determine the final volume. This can be obtained as follow:

Initial volume (V₁) = 5.33 L

Initial temperature (T₁) = 294 K

Final temperature (T₂) = 283 K

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

5.33 / 294 = V₂ / 283

Cross multiply

294 × V₂ = 5.33 × 283

294 × V₂ = 1508.39

Divide both side by 294

V₂ = 1508.39 / 294

V₂ = 5.13 L

Thus, the new volume of the football is 5.13 L

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