Calculate the molecular weight of 0.2g H3X solution if 50ml of this acid neutralized with 40ml of 0.03N Ca(oH)2 then calculate strength of this solution in ppm

1. Molecular weight = 333.3 g/mol

2. Strenght = 2222.2 mg/L

Explanation:

First, we need to find molarity (M) from normality (N) as follows:

Where n is the number of OH⁻ = 2

Now, when the H₃X solution is neutralized with Ca(OH)₂ we have:

Hence, the molecular weight (MW) of H₃X is:    

Finally, we can calculate the strength (S) of this solution in ppm as follows:

I hope it helps you!

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