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Calculate AEfor a system that absorbs 599,0 kJ of heat from its surroundings
and does 3510 kJ of work on its surroundings.

-2911 kJ

Explanation:

Step 1: Given data

Step 2: Calculate the change in the internal energy (ΔE)

We will use the following expression.

ΔE = Q + W

ΔE = 599.0 kJ + (-3510 kJ) = -2911 kJ

idk

explanation:

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.