Determine the hydronium ion concentration Big Points in a solution that is 0.00013 M HCl.

Answer in units of M.

040 (part 2 of 2) 10.0 points

Determine the hydroxide ion concentration in

a solution that is 0.00013 M HCl.

Answer in units of M.

[H⁺] = 0.00013 M

[OH⁻] = 7.7 × 10⁻¹¹ M

Explanation:

Step 1: Calculate the concentration of H⁺ ions

HCl is a strong acid that dissociates according to the following equation.

HCl ⇒ H⁺ + Cl⁻

The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.

Step 2: Calculate the concentration of OH⁻ ions

We will use the ionic product of water equation.

Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]

[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied