Please help please with the answers

1) We know that rtp = number of moles × 24

                                 = 0.25 × 24

                                 = 6 dm³

Therefore the volume of 0.25 moles of gas at rtp is A) 6 dm³

3.1) Amount of Copper = 20 tonnes

Amount of pure copper from impure copper = 18 tonnes

Purity of copper = (Pure copper/ impure copper) × 100

                           = (18 / 20) × 100

                           = 18 × 5

                           = 90 %

Therefore the purity of copper is 90%

3.2) We know that oxygen has 8 protons and 8 neutrons, so the weight of oxygen molecule is 8 + 8 = 16 u

So, one mole of oxygen weighs 16 g, so 2 moles weigh 2 × 16 = 32 grams

But oxygen is diatomic so the weight is 32 × 2 = 64 grams

Therefore the weight of 2 moles of oxygen is 64 grams

3.3) Concentration of solution = Amount of solute/volume

                                                   = 4 moles/ 2 dm³

                                                   = 4 / 2

                                                   = 2 mol/dm³

Therefore the concentration of a solution containing 4 moles in 2 dm³ of solution is 2 mol/dm³

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Extremely sorry for the late answer

the answer is option a.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.